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Physics · UNITS AND MEASUREMENT

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If the relative density of lead is \( 11.3 \), what is its density in \( \text{kg m}^{-3} \)?

  1. \( 1.13 \times 10^3\text{ kg m}^{-3} \)
  2. \( 1.13 \times 10^4\text{ kg m}^{-3} \)
  3. \( 1.13 \times 10^2\text{ kg m}^{-3} \)
  4. \( 11.3\text{ kg m}^{-3} \)

Correct answer · Option 2

\( 1.13 \times 10^4\text{ kg m}^{-3} \)

Explanation

Density in \( \text{kg m}^{-3} \) is obtained by multiplying relative density by the density of water (\( 10^3\text{ kg m}^{-3} \)), giving \( 11.3 \times 10^3 = 1.13 \times 10^4\text{ kg m}^{-3} \).
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