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Chemistry · EQUILIBRIUM
हिन्दीThe solubility product (\( K_{\text{sp}} \)) of a sparingly soluble salt \( \text{A}_2\text{X}_3 \) is \( 1.08 \times 10^{-23} \). Its molar solubility (\( S \)) in pure water is:
Correct answer · Option 1
\( 1.0 \times 10^{-5} \text{ mol L}^{-1} \)
Explanation
For \( \text{A}_2\text{X}_3 \), \( K_{\text{sp}} = (2S)^2(3S)^3 = 108 S^5 \). So \( 108 S^5 = 1.08 \times 10^{-23} \implies S^5 = 10^{-25} \implies S = 1.0 \times 10^{-5} \text{ mol L}^{-1} \).
