Physics · PYQ NEET UG 2016(1)
हिन्दीAn electron of mass \( m \) and a photon have same energy \( E \). The ratio of de-Broglie wavelengths associated with them is (\( c \) being velocity of light)
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Correct answer · Option A
\( \frac{1}{c} (\frac{E}{2m})^{\frac{1}{2}} \)
Explanation
For electron: \( \lambda_e = \frac{h}{\sqrt{2mE}} \). For photon: \( \lambda_p = \frac{hc}{E} \). Ratio \( \frac{\lambda_e}{\lambda_p} = \frac{h}{\sqrt{2mE}} \cdot \frac{E}{hc} = \frac{1}{c} \sqrt{\frac{E}{2m}} \).