OnlineCBT
Physics · UNITS AND MEASUREMENT
हिन्दीA student measures the thickness of a wire using a screw gauge. The main scale reading is \( 0\text{ mm} \) and the circular scale reading is \( 52\text{ divisions} \). Given that the pitch of the screw gauge is \( 1\text{ mm} \) and it has \( 100\text{ divisions} \) on its circular scale, the measured diameter of the wire is:
Correct answer · Option 1
\( 0.052\text{ cm} \)
Explanation
Least count \( = \frac{1\text{ mm}}{100} = 0.01\text{ mm} = 0.001\text{ cm} \). Diameter \( = 0 + 52 \times 0.001\text{ cm} = 0.052\text{ cm} \).
