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Chemistry · EQUILIBRIUM

हिन्दी

For the hydrolysis of sucrose at \( 300\text{ K} \), the equilibrium constant is \( K = 2.0 \times 10^{13} \). What is the standard Gibbs energy change \( \Delta G^\circ \) for this reaction? (Given: \( R = 8.314\text{ J mol}^{-1}\text{K}^{-1} \), \( \ln(2.0 \times 10^{13}) = 30.627 \))

  1. \( +7.64 \times 10^4\text{ J mol}^{-1} \)
  2. \( -3.82 \times 10^4\text{ J mol}^{-1} \)
  3. \( -7.64 \times 10^4\text{ J mol}^{-1} \)
  4. \( +3.82 \times 10^4\text{ J mol}^{-1} \)

Correct answer · Option 3

\( -7.64 \times 10^4\text{ J mol}^{-1} \)

Explanation

\( \Delta G^\circ = -RT \ln K = -(8.314)(300)(30.627) \approx -7.64 \times 10^4\text{ J mol}^{-1} \).
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