Chemistry · THERMODYNAMICS
हिन्दीGiven the standard enthalpies of formation: \( \Delta_f H^\ominus[\text{CO}(g)] = -110.53\text{ kJ mol}^{-1} \) and \( \Delta_f H^\ominus[\text{CO}_2(g)] = -393.51\text{ kJ mol}^{-1} \). The standard enthalpy change (\( \Delta_r H^\ominus \)) for the reaction \( \text{CO}(g) + \frac{1}{2}\text{O}_2(g) \rightarrow \text{CO}_2(g) \) is:
Correct answer · Option 1
-282.98 kJ mol⁻¹
Explanation
\( \Delta_r H^\ominus = \Delta_f H^\ominus(\text{CO}_2) - \Delta_f H^\ominus(\text{CO}) = -393.51 - (-110.53) = -282.98\text{ kJ mol}^{-1} \).