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Physics · MOTION IN A PLANE
हिन्दीA projectile is launched from ground level. If its horizontal range is numerically equal to its maximum height, the angle of projection \( \theta \) is:
Correct answer · Option 4
\( \tan^{-1}(4) \)
Explanation
\( R = h_m \implies \frac{v_o^2\sin 2\theta}{g} = \frac{v_o^2\sin^2\theta}{2g} \implies 2\sin\theta\cos\theta = \frac{\sin^2\theta}{2} \implies \tan\theta = 4 \implies \theta = \tan^{-1}(4) \).
