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Physics · PYQ NEET UG 2026
हिन्दीConsider a particle moving along a straight line, whose position as a function of time is given by $s(t) = \alpha t^2 - \beta t + \gamma$, where $\alpha = 1 \text{ ms}^{-2}$, $\beta = 6 \text{ ms}^{-1}$ and $\gamma = 5 \text{ m}$. The average speed of the particle, in $\text{ms}^{-1}$, from $t=0$ to $t=6 \text{ s}$ is :
Correct answer · Option 3
3
Explanation
Velocity $v(t) = \frac{ds}{dt} = 2\alpha t - \beta = 2(1)t - 6 = 2t - 6$. Velocity becomes zero at $t = 3\text{ s}$. Total distance traveled from $t=0$ to $6\text{ s}$ divided by time interval gives average speed = $3\text{ ms}^{-1}$.
