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Physics · MOTION IN A STRAIGHT LINE
हिन्दीA stone is released from a balloon rising vertically upwards with a constant velocity of \( 10 \text{ m/s} \). The stone reaches the ground after \( 6.0 \text{ seconds} \). Taking \( g = 10 \text{ m/s}^2 \), find the height of the balloon above the ground at the moment the stone hits the ground.
Correct answer · Option 2
\( 180 \text{ m} \)
Explanation
Displacement of stone from release point: \( y = v_0 t - \frac{1}{2} g t^2 = 10(6) - 5(36) = -120 \text{ m} \). So balloon height at release was \( 120 \text{ m} \). In 6 s, balloon rises an additional \( 10 \times 6 = 60 \text{ m} \). Total height of balloon when stone hits ground = \( 120 + 60 = 180 \text{ m} \).
