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Physics · MOTION IN A STRAIGHT LINE
हिन्दीA body moving with uniform acceleration along a straight path covers a distance of \( 40\text{ m} \) in \( 4\text{ s} \). If its velocity at the end of this interval is \( 15\text{ m s}^{-1} \), what was its initial velocity \( v_0 \)?
Correct answer · Option 3
\( 5.0\text{ m s}^{-1} \)
Explanation
Using \( x = (\frac{v + v_0}{2}) t \), we have \( 40 = (\frac{15 + v_0}{2}) \times 4 \implies 20 = 15 + v_0 \implies v_0 = 5.0\text{ m s}^{-1} \).
