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Physics · MOTION IN A PLANE
हिन्दीA particle is projected from the ground with an initial velocity \( \mathbf{v}_0 = u\hat{i} + v\hat{j} \). If the horizontal range of the projectile is equal to twice its maximum height (\( R = 2H \)), then the ratio \( \frac{v}{u} \) is:
Correct answer · Option 3
\( 2 \)
Explanation
Range \( R = \frac{2uv}{g} \) and maximum height \( H = \frac{v^2}{2g} \). Given \( R = 2H \implies \frac{2uv}{g} = 2(\frac{v^2}{2g}) = \frac{v^2}{g} \implies 2u = v \implies \frac{v}{u} = 2 \).
