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Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE
हिन्दीWater (\( \text{H}_2\text{O} \)) has a net dipole moment of \( 1.85\text{ D} \) and a bond angle of \( 104.5^\circ \). Treating each \( \text{O}-\text{H} \) bond dipole as \( \mu_{\text{bond}} \), and using \( \mu_{\text{net}} = 2\mu_{\text{bond}}\cos(\theta/2) \) where \( \cos(52.25^\circ) \approx 0.612 \), the individual \( \text{O}-\text{H} \) bond dipole moment is:
Correct answer · Option 3
\( 1.51\text{ D} \)
Explanation
\( \mu_{\text{net}} = 2\mu_{\text{bond}}\cos(52.25^\circ) \implies 1.85 = 2 \times \mu_{\text{bond}} \times 0.612 \implies \mu_{\text{bond}} = \frac{1.85}{1.224} \approx 1.51\text{ D} \).
