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Physics · GRAVITATION
हिन्दीThe orbital radius of the Moon is \( R_m \approx 3.84 \times 10^8\text{ m} \) and its time period is \( T \approx 27.3\text{ days} \approx 2.36 \times 10^6\text{ s} \). The ratio of Earth's surface gravity \( g \approx 9.8\text{ m/s}^2 \) to the centripetal acceleration of the Moon \( a_m \) is approximately:
Correct answer · Option 1
\( 3600 \)
Explanation
Using \( a_m = \frac{4\pi^2 R_m}{T^2} \approx 2.7 \times 10^{-3}\text{ m/s}^2 \), the ratio is \( \frac{g}{a_m} = (\frac{R_m}{R_E})^2 \approx 60^2 = 3600 \).
