OnlineCBT
Chemistry · PYQ NEET UG 2020
हिन्दीAn element has a body centered cubic (bcc) structure with a cell edge of \( 288 \text{ pm} \). The atomic radius is _______.
Correct answer · Option 4
\( \frac{\sqrt{3}}{4} \times 288 \text{ pm} \)
Explanation
For bcc lattice, the relation between atomic radius \( r \) and edge length \( a \) is \( r = \frac{\sqrt{3}}{4}a \). Thus, \( r = \frac{\sqrt{3}}{4} \times 288 \text{ pm} \).
