OnlineCBT Logo OnlineCBT

Physics · MOTION IN A PLANE

हिन्दी

Two vectors \( \mathbf{A} \) and \( \mathbf{B} \) have equal magnitudes \( A \) and are separated by an angle \( \theta \). If their resultant vector \( \mathbf{R} \) makes an angle \( \alpha \) with vector \( \mathbf{A} \), determine the relation between \( \alpha \) and \( \theta \), and the expression for the magnitude of \( \mathbf{R} \).

  1. \( \alpha = \theta \), \( R = 2A \sin(\theta/2) \)
  2. \( \alpha = \theta/2 \), \( R = 2A \sin(\theta/2) \)
  3. \( \alpha = \theta/3 \), \( R = A \cos(\theta/2) \)
  4. \( \alpha = \theta/2 \), \( R = 2A \cos(\theta/2) \)

Correct answer · Option 4

\( \alpha = \theta/2 \), \( R = 2A \cos(\theta/2) \)

Explanation

For equal magnitude vectors, the resultant bisects the angle, so \( \alpha = \theta/2 \). Magnitude \( R = \sqrt{A^2 + A^2 + 2A^2\cos\theta} = \sqrt{2A^2(1+\cos\theta)} = 2A\cos(\theta/2) \).
पता संपर्क करें

+91 7877547686

ई-मेल

onlinecbtportal@gmail.com

हेल्पलाइन नंबर

+91 7877547686


डाउनलोड करने के लिए क्लिक करें
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat