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Physics · PYQ NEET UG 2019(1)
हिन्दीWhen a block of mass M is suspended by a long wire of length L, the length of the wire becomes \( (L + l) \). The elastic potential energy stored in the extended wire is:
Correct answer · Option 1
\( \frac{1}{2} Mgl \)
Explanation
Elastic potential energy \( U = \frac{1}{2} \times \text{load} \times \text{extension} = \frac{1}{2} Mgl \).
