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Physics · LAWS OF MOTION

हिन्दी

A body of mass \( m \) is connected between two identical light springs, each of spring constant \( k \), arranged in parallel on a horizontal frictionless table. If the body is pulled horizontally so that the system experiences a total stretch of \( x \), the work done against the net restoring spring force is:

  1. \( \frac{1}{2} k x^2 \)
  2. \( k x^2 \)
  3. \( 2 k x^2 \)
  4. \( \frac{1}{4} k x^2 \)

Correct answer · Option 2

\( k x^2 \)

Explanation

For parallel springs, equivalent spring constant \( k_{eq} = k + k = 2k \). Work done against restoring force is \( W = \frac{1}{2} k_{eq} x^2 = \frac{1}{2} (2k) x^2 = k x^2 \).
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