OnlineCBT
Physics · MOTION IN A PLANE
हिन्दीA particle moves in a circular path of radius \( R = 2\text{ m} \) with a constant speed of \( v = 10\text{ m/s} \). The magnitude of centripetal acceleration of the particle is:
Correct answer · Option 4
50 m/s²
Explanation
\( a_c = \frac{v^2}{R} = \frac{10^2}{2} = \frac{100}{2} = 50\text{ m/s}^2 \).
