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Physics · PYQ NEET UG 2021

हिन्दी

A small block slides down on a smooth inclined plane, starting from rest at time t = 0. Let \( S_n \) be the distance travelled by the block in the interval t = n - 1 to t = n. Then, the ratio \( \frac{S_n}{S_{n+1}} \) is:

  1. \( \frac{2n - 1}{2n + 1} \)
  2. \( \frac{2n + 1}{2n - 1} \)
  3. \( \frac{2n}{2n - 1} \)
  4. \( \frac{2n - 1}{2n} \)

Correct answer · Option 1

\( \frac{2n - 1}{2n + 1} \)

Explanation

The distance travelled in the \( n \)-th second starting from rest is given by \( S_n = \frac{a}{2}(2n - 1) \). Therefore, \( \frac{S_n}{S_{n+1}} = \frac{2n - 1}{2(n+1) - 1} = \frac{2n - 1}{2n + 1} \).
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