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Chemistry · Some Basic Concepts of Chemistry
हिन्दीThe density of a \( 3\text{ M} \) solution of \( \text{NaCl} \) is \( 1.25\text{ g mL}^{-1} \). Calculate the molality of the solution.
Correct answer · Option 2
2.79 m
Explanation
Mass of 1 L solution = \( 1250\text{ g} \); Mass of NaCl = \( 175.5\text{ g} \); Mass of solvent = \( 1074.5\text{ g} \). Molality = \( \frac{3}{1.0745} = 2.79\text{ m} \).
