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Physics · WORK, ENERGY AND POWER
हिन्दीA particle of mass \( m \) moves under the action of a constant power source delivering power \( P \). Starting from rest at \( t = 0 \), the distance covered by the particle as a function of time \( t \) is proportional to:
View Answer & Solution
Correct answer · Option D
\( t^{3/2} \)
Explanation
\( P = F v = m v \frac{dv}{dt} \implies v dv = \frac{P}{m} dt \implies v = \sqrt{\frac{2P}{m}} t^{1/2} \). Distance \( x = \int v dt \propto t^{3/2} \).
