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Chemistry · PYQ NEET UG 2019(1)
हिन्दीPH of a saturated solution of \( \text{Ca(OH)}_2 \) is 9. The solubility product (\( K_{sp} \)) of \( \text{Ca(OH)}_2 \) is ______.
Correct answer · Option 4
\( 0.5 \times 10^{-15} \)
Explanation
Given \( \text{pH} = 9 \implies \text{pOH} = 5 \implies [\text{OH}^-] = 10^{-5} \text{ M} \). Solubility \( s = \frac{[\text{OH}^-]}{2} = 5 \times 10^{-6} \text{ M} \). \( K_{sp} = 4s^3 = 4(5 \times 10^{-6})^3 = 0.5 \times 10^{-15} \).
