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Biology · PRINCIPLES OF INHERITANCE AND VARIATION
हिन्दीA man with blood group AB (\( I^A I^B \)) marries a woman with blood group A whose father had blood group O (\( ii \)). What is the probability that their first child will be a male with blood group B, and what is the total number of different genotypes possible in their offspring?
Correct answer · Option 1
Probability = 1/8, Total genotypes = 4
Explanation
Father is \( I^A I^B \), Mother is \( I^A i \). Offspring genotypes: \( I^A I^A \), \( I^A i \), \( I^A I^B \), \( I^B i \) (4 distinct genotypes). Blood group B phenotype corresponds to \( I^B i \) (1/4 chance). Probability of male child = 1/2. Combined probability = 1/4 × 1/2 = 1/8.
