OnlineCBT
Physics · MOTION IN A STRAIGHT LINE
हिन्दीA body moving with uniform acceleration along a straight line covers \( 10\text{ m} \) in the \( 2^{\text{nd}} \) second and \( 20\text{ m} \) in the \( 4^{\text{th}} \) second. The distance covered by the body in the \( 6^{\text{th}} \) second is:
Correct answer · Option 4
\( 30\text{ m} \)
Explanation
\( D_n = u + \frac{a}{2}(2n-1) \). Given \( D_2 = u + \frac{3a}{2} = 10 \) and \( D_4 = u + \frac{7a}{2} = 20 \). Subtracting gives \( 2a = 10 \implies a = 5\text{ m/s}^2 \). Then \( u = 2.5\text{ m/s} \). For \( n=6 \): \( D_6 = 2.5 + \frac{5}{2}(11) = 30\text{ m} \).
