OnlineCBT Logo OnlineCBT

Chemistry · PYQ NEET UG 2018

हिन्दी

The bond dissociation energies of \( \mathrm{X}_{2}, \mathrm{Y}_{2} \) and \( \mathrm{XY} \) are in the ratio of \( 1:0.5:1 \). \( \Delta \mathrm{H} \) for the formation of \( \mathrm{XY} \) is \( -200 \mathrm{~kJ} \mathrm{~mol}^{-1} \). The bond dissociation energy of \( \mathrm{X}_{2} \) will be

  1. A
    \( 200 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
  2. B
    \( 100 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
  3. C
    \( 800 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
  4. D
    \( 400 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
View Answer & Solution

Correct answer · Option C

\( 800 \mathrm{~kJ} \mathrm{~mol}^{-1} \)

Explanation

Let bond energies be \( x, 0.5x, x \). Enthalpy of formation \( \Delta H = \sum BE(reactants) - \sum BE(products) \). Solving gives \( x = 800 \mathrm{~kJ} \mathrm{~mol}^{-1} \).
Address Contact

+91 7877547686

E-mail

onlinecbtportal@gmail.com

Helpline Number

+91 7877547686


Click To Download
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat