Chemistry · PYQ NEET UG 2018
हिन्दीThe bond dissociation energies of \( \mathrm{X}_{2}, \mathrm{Y}_{2} \) and \( \mathrm{XY} \) are in the ratio of \( 1:0.5:1 \). \( \Delta \mathrm{H} \) for the formation of \( \mathrm{XY} \) is \( -200 \mathrm{~kJ} \mathrm{~mol}^{-1} \). The bond dissociation energy of \( \mathrm{X}_{2} \) will be
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Correct answer · Option C
\( 800 \mathrm{~kJ} \mathrm{~mol}^{-1} \)
Explanation
Let bond energies be \( x, 0.5x, x \). Enthalpy of formation \( \Delta H = \sum BE(reactants) - \sum BE(products) \). Solving gives \( x = 800 \mathrm{~kJ} \mathrm{~mol}^{-1} \).