OnlineCBT
Chemistry · Structure of atom
हिन्दीDetermine the radius of the third stationary orbit (\( n = 3 \)) for a single-electron species \( \text{Li}^{2+1} \) (where \( a_0 = 52.9 \text{ pm} \)).
Correct answer · Option 1
\( 158.7 \text{ pm} \)
Explanation
Using \( r_n = \frac{a_0 n^2}{Z} \), for \( n = 3 \) and \( Z = 3 \) for \( \text{Li}^{2+} \), \( r_3 = \frac{52.9 \times 3^2}{3} = 3 \times 52.9 = 158.7 \text{ pm} \) is incorrect; wait, \( 52.9 \times 9 / 3 = 158.7 \text{ pm} \). Let's check options: Option 1 is 158.7 pm.
