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Chemistry · THERMODYNAMICS

हिन्दी

An ideal gas undergoes compression in two stages: First, against a constant pressure of \( 2.0\text{ atm} \) from \( 10\text{ L} \) to \( 6\text{ L} \), and Second, against a constant pressure of \( 4.0\text{ atm} \) from \( 6\text{ L} \) to \( 3\text{ L} \). The total work done on the gas in litre-atmospheres is:

  1. \( 20.0\text{ L}\cdot\text{atm} \)
  2. \( 8.0\text{ L}\cdot\text{atm} \)
  3. \( 12.0\text{ L}\cdot\text{atm} \)
  4. \( 28.0\text{ L}\cdot\text{atm} \)

Correct answer · Option 1

\( 20.0\text{ L}\cdot\text{atm} \)

Explanation

\( w_1 = -p_1\Delta V_1 = -2.0(6 - 10) = +8.0\text{ L}\cdot\text{atm} \). \( w_2 = -p_2\Delta V_2 = -4.0(3 - 6) = +12.0\text{ L}\cdot\text{atm} \). \( w_{\text{total}} = 8.0 + 12.0 = 20.0\text{ L}\cdot\text{atm} \).
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