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Physics · LAWS OF MOTION

हिन्दी

A bullet moving with speed \( v \) penetrates a distance \( s \) into a fixed wooden block before coming to rest. Assuming the resistive force of the wood is constant, the penetration distance for a bullet of identical mass entering the same block with double the initial speed \( 2v \) will be:

  1. \( 2s \)
  2. \( 4s \)
  3. \( 8s \)
  4. \( s \sqrt{2} \)

Correct answer · Option 2

\( 4s \)

Explanation

From \( v^2 - u^2 = 2as \implies s = \frac{u^2}{2a} \), penetration distance is proportional to \( u^2 \). Doubling speed increases distance by a factor of \( 2^2 = 4 \).
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