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Physics · GRAVITATION
हिन्दीThe work done in lifting a particle of mass \( m \) radially from a distance \( r_1 = R_E \) to \( r_2 = 3 R_E \) from the center of the Earth of mass \( M_E \) and radius \( R_E \) is:
Correct answer · Option 3
\( \frac{2}{3} m g R_E \)
Explanation
\( W_{12} = -G M_E m (\frac{1}{r_2} - \frac{1}{r_1}) = -G M_E m (\frac{1}{3 R_E} - \frac{1}{R_E}) = \frac{2 G M_E m}{3 R_E} = \frac{2}{3} m g R_E \).
