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Physics · GRAVITATION
हिन्दीFor a satellite of mass \( m \) moving in a circular orbit of radius \( r \) around the Earth, the ratio of its kinetic energy (\( K.E. \)) to its total mechanical energy (\( E \)) is:
Correct answer · Option 3
\( -1 : 1 \)
Explanation
Kinetic energy is \( K.E. = \frac{GM_E m}{2r} \) and total energy is \( E = -\frac{GM_E m}{2r} \), hence \( K.E./E = -1 \).
