OnlineCBT Logo OnlineCBT

Physics · WORK, ENERGY AND POWER

हिन्दी

A bob of mass \( m \) is suspended by a light string of length \( L \). What minimum horizontal velocity \( v_0 \) must be imparted to the bob at its lowest point so that it completes a full vertical circular loop?

  1. \( \sqrt{3gL} \)
  2. \( \sqrt{5gL} \)
  3. \( \sqrt{4gL} \)
  4. \( \sqrt{2gL} \)

Correct answer · Option 2

\( \sqrt{5gL} \)

Explanation

At the topmost point C, the condition for completing the circle is \( T_C \ge 0 \implies v_C = \sqrt{gL} \). By conservation of mechanical energy, \( \frac{1}{2}mv_0^2 = \frac{1}{2}m v_C^2 + 2mgL \), which yields \( v_0 = \sqrt{5gL} \).
पता संपर्क करें

+91 7877547686

ई-मेल

onlinecbtportal@gmail.com

हेल्पलाइन नंबर

+91 7877547686


डाउनलोड करने के लिए क्लिक करें
Get it on Google Play

ऐप डाउनलोड करने
के लिए Google Play पर
उपलब्ध है

WhatsApp Chat