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Physics · WORK, ENERGY AND POWER

हिन्दी

A bob of mass \( m \) is suspended by a light string of length \( L \). What minimum horizontal velocity \( v_0 \) must be imparted to the bob at its lowest point so that it completes a full vertical circular loop?

  1. A
    \( \sqrt{3gL} \)
  2. B
    \( \sqrt{5gL} \)
  3. C
    \( \sqrt{4gL} \)
  4. D
    \( \sqrt{2gL} \)
View Answer & Solution

Correct answer · Option B

\( \sqrt{5gL} \)

Explanation

At the topmost point C, the condition for completing the circle is \( T_C \ge 0 \implies v_C = \sqrt{gL} \). By conservation of mechanical energy, \( \frac{1}{2}mv_0^2 = \frac{1}{2}m v_C^2 + 2mgL \), which yields \( v_0 = \sqrt{5gL} \).
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