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Physics · PYQ NEET UG 2021

हिन्दी

Two charged spherical conductors of radius \( R_1 \) and \( R_2 \) are connected by a wire. Then the ratio of surface charge densities of the spheres (\( \sigma_1 / \sigma_2 \)) is:

  1. \( \frac{R_2}{R_1} \)
  2. \( (\frac{R_1}{R_2})^2 \)
  3. \( \frac{R_1^2}{R_2^2} \)
  4. \( \frac{R_1}{R_2} \)

Correct answer · Option 1

\( \frac{R_2}{R_1} \)

Explanation

When connected, both spheres attain the same potential \( V_1 = V_2 \implies \frac{Q_1}{R_1} = \frac{Q_2}{R_2} \). Surface charge density \( \sigma = \frac{Q}{4\pi R^2} \), so \( \sigma R = \text{constant} \). Thus, \( \frac{\sigma_1}{\sigma_2} = \frac{R_2}{R_1} \).
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