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Chemistry · PYQ NEET UG 2023

हिन्दी

The conductivity of centimolar solution of \( \mathrm{KCl} \) at \( 25^{\circ} \mathrm{C} \) is \( 0.0210 \text{ ohm}^{-1} \text{ cm}^{-1} \) and the resistance of the cell containing the solution at \( 25^{\circ} \mathrm{C} \) is \( 60 \text{ ohm} \). The value of cell constant is -

  1. \( 1.34 \text{ cm}^{-1} \)
  2. \( 3.28 \text{ cm}^{-1} \)
  3. \( 3.34 \text{ cm}^{-1} \)
  4. \( 1.26 \text{ cm}^{-1} \)

Correct answer · Option 4

\( 1.26 \text{ cm}^{-1} \)

Explanation

Cell constant \( (\frac{l}{A}) = \text{Conductivity } (\kappa) \times \text{Resistance } (R) = 0.0210 \times 60 = 1.26 \text{ cm}^{-1} \).
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