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Physics · LAWS OF MOTION
हिन्दीA constant force \( F \) applied individually to a mass \( m_1 \) produces an acceleration of \( 12\text{ m/s}^2 \), and applied to mass \( m_2 \) produces an acceleration of \( 6\text{ m/s}^2 \). If both masses are tied tightly together and pulled by the same force \( F \), the resulting acceleration will be:
Correct answer · Option 2
4 m/s²
Explanation
Here \( m_1 = \frac{F}{12} \) and \( m_2 = \frac{F}{6} \). Total mass \( M = m_1 + m_2 = F (\frac{1}{12} + \frac{1}{6}) = \frac{F}{4} \). Acceleration \( a = \frac{F}{M} = 4\text{ m/s}^2 \).
