N adiabatic expansion, the temperature of one mole of an ideal monatomic gas ( \gamma = 5/3 ) decreases from 60K to 50K. The work done by the gas in the process is : (Take the universal gas constant as R = 8.3 \text{ J mol}^{-1}\text{ K}^{-1})

For an adiabatic process, work done ( W = -\Delta U = -n C_v \Delta T ). For monatomic gas, ( C_v = \frac{3}{2}R ). Thus, ( W = -1 \times \frac{3}{2} \times 8.3 \times (50 - 60) = 1.5 \times 8.3 \times 10 = 124.5 \text{ J} )? Wait, ( C_v = \frac{3}{2}R ), ( W = -\frac{3}{2}R(T_2 - T_1) = -1.5 \times 8.3 \times (-10) = 124.5 \text{ J} ). Let's check calculation: 1.5 * 83 = 124.5.