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Physics · PYQ NEET UG 2020
हिन्दीA resistance wire connected in the left gap of a metre bridge balances a \( 10\ \Omega \) resistance in the right gap at a point which divides the bridge wire in the ratio \( 3 : 2 \). If the length of the resistance wire is \( 1.5\text{ m} \), then the length of \( 1\ \Omega \) of the resistance wire is:
Correct answer · Option 1
\( 1.0 \times 10^{-1}\text{ m} \)
Explanation
Using metre bridge balance condition, \( \frac{R}{10} = \frac{3}{2} \implies R = 15\ \Omega \). Length per ohm = \( \frac{1.5\text{ m}}{15\ \Omega} = 0.1\text{ m} = 1.0 \times 10^{-1}\text{ m} \).
