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Chemistry · Classification of Elements and Periodicity in Properties
हिन्दीBased on the periodic trends in atomic and ionic radii from the table on page 5, what is the metallic radius difference \( \Delta r = r(\text{Na}) - r(\text{Li}) \) in pm?
Correct answer · Option 1
\( 34 \text{ pm} \)
Explanation
From the table on page 5, metallic radius of Na is 186 pm and Li is 152 pm. Therefore, \( \Delta r = 186 - 152 = 34 \text{ pm} \).
