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Chemistry · THERMODYNAMICS

हिन्दी

For the reversible isothermal expansion of \( n \) moles of an ideal gas from volume \( V_i \) to \( V_f \), the work done by the system is given by:

  1. \( w_{\text{rev}} = +2.303\, nRT \log(\frac{V_f}{V_i}) \)
  2. \( w_{\text{rev}} = -2.303\, nRT \log(\frac{V_f}{V_i}) \)
  3. \( w_{\text{rev}} = -nRT (\frac{V_f - V_i}{V_i}) \)
  4. \( w_{\text{rev}} = -2.303\, nRT \log(\frac{V_i}{V_f}) \)

Correct answer · Option 2

\( w_{\text{rev}} = -2.303\, nRT \log(\frac{V_f}{V_i}) \)

Explanation

For reversible isothermal expansion, \( w_{\text{rev}} = -\int p\, dV = -nRT \ln(V_f / V_i) = -2.303\, nRT \log(V_f / V_i) \).
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