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Chemistry · THERMODYNAMICS
हिन्दीFor 3.0 moles of an ideal gas, the temperature is increased by 40.0 K. The difference between the heat absorbed at constant pressure and the heat absorbed at constant volume (\( q_p - q_v \)) is: (Take \( R = 8.314\text{ J mol}^{-1}\text{ K}^{-1} \))
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Correct answer · Option A
997.7 J
Explanation
\( q_p - q_v = \Delta H - \Delta U = n R \Delta T = 3.0 \times 8.314 \times 40.0 = 997.68\text{ J} \approx 997.7\text{ J} \).
