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Physics · PYQ NEET UG 2019(2)
हिन्दीA solid cylinder of mass 2 kg and radius 50 cm rolls up an inclined plane of angle of inclination \( 30^\circ \). The centre of mass of the cylinder has speed of 4 m/s. The distance travelled by the cylinder on the inclined surface will be, [take \( g = 10\text{ m/s}^2 \)]
Correct answer · Option 1
2.4 m
Explanation
By conservation of energy, translational + rotational kinetic energy = potential energy: \( \frac{1}{2}mv^2(1 + \frac{k^2}{R^2}) = mgh \). For a solid cylinder, \( \frac{k^2}{R^2} = \frac{1}{2} \). Thus, \( \frac{3}{4}v^2 = g d \sin\theta \). Substituting values gives distance \( d = 2.4\text{ m} \).
