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Physics · PYQ NEET UG 2016(1)
हिन्दीA black body is at a temperature of \( 5760\text{ K} \). The energy of radiation emitted by the body at wavelength \( 250\text{ nm} \) is \( U_1 \), at wavelength \( 500\text{ nm} \) is \( U_2 \) and that at \( 1000\text{ nm} \) is \( U_3 \). Wien's constant, \( b = 2.88 \times 10^6\text{ nmK} \). Which of the following is correct?
Correct answer · Option 1
\( U_2 > U_1 \)
Explanation
Peak emission wavelength using Wien's law is \( \lambda_m = \frac{b}{T} = \frac{2.88 \times 10^6}{5760} = 500\text{ nm} \). Thus, energy emission is maximum at \( \lambda = 500\text{ nm} \), meaning \( U_2 > U_1 \).
