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Physics · PYQ NEET UG 2016(1)

हिन्दी

When an \( \alpha \)-particle of mass \( m \) moving with velocity \( v \) bombards on heavy nucleus of charge '\( Ze \)', its distance of closest approach from the nucleus depends on \( m \) as

  1. \( \frac{1}{m} \)
  2. \( m \)
  3. \( \frac{1}{m^2} \)
  4. \( \frac{1}{\sqrt{m}} \)

Correct answer · Option 1

\( \frac{1}{m} \)

Explanation

Distance of closest approach \( r_0 = \frac{1}{4\pi\varepsilon_0} \frac{2Ze^2}{(1/2)mv^2} \). Thus, \( r_0 \propto \frac{1}{m} \).
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