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Chemistry · EQUILIBRIUM
हिन्दीAccording to Henry's law, the mass of a gas dissolved per unit volume of a liquid is directly proportional to its partial pressure. In an experiment, \( 0.044\text{ g} \) of \( \text{CO}_2 \) dissolves in \( 100\text{ mL} \) of water under a \( \text{CO}_2 \) partial pressure of \( 2.0\text{ atm} \). What total mass of \( \text{CO}_2 \) (in grams) will dissolve in \( 250\text{ mL} \) of water if the \( \text{CO}_2 \) partial pressure is increased to \( 5.0\text{ atm} \) at the same temperature?
Correct answer · Option 1
0.275 g
Explanation
Mass dissolved per 100 mL at 5 atm = \( 0.044 \times (5.0 / 2.0) = 0.110\text{ g} \). For 250 mL of water, total mass dissolved = \( 0.110 \times (250 / 100) = 0.275\text{ g} \).
