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Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीThree particles of masses \( 100\text{ g} \), \( 150\text{ g} \), and \( 200\text{ g} \) are placed at the vertices of an equilateral triangle of side \( 0.5\text{ m} \). The \( 100\text{ g} \) mass is at \( (0,0) \), \( 150\text{ g} \) is at \( (0.5\text{ m}, 0) \), and \( 200\text{ g} \) is at \( (0.25\text{ m}, 0.25\sqrt{3}\text{ m}) \). The \( X \)-coordinate of the centre of mass is:
Correct answer · Option 1
\( \frac{5}{18}\text{ m} \)
Explanation
\( X = \frac{100(0) + 150(0.5) + 200(0.25)}{100 + 150 + 200} = \frac{75 + 50}{450} = \frac{125}{450} = \frac{5}{18}\text{ m} \).
