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Physics · PYQ NEET UG 2022
हिन्दीTwo resistors of resistance, \( 100\ \Omega \) and \( 200\ \Omega \) are connected in parallel in an electrical circuit. The ratio of the thermal energy developed in \( 100\ \Omega \) to that in \( 200\ \Omega \) in a given time is:
Correct answer · Option 4
\( 2 : 1 \)
Explanation
In a parallel connection, potential difference \( V \) across both resistors is the same. Thermal energy developed is given by \( H = \frac{V^2}{R}t \), so \( \frac{H_1}{H_2} = \frac{R_2}{R_1} = \frac{200}{100} = 2 : 1 \).
