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Chemistry · CHEMICAL BONDING AND MOLECULAR STRUCTURE
हिन्दीConsider the following molecules: \( \text{BeCl}_2 \), \( \text{BF}_3 \), \( \text{CH}_4 \), \( \text{PCl}_5 \), and \( \text{SF}_6 \). If \( N_e \) is the sum of total valence shell electron pairs (bond pairs) around their central atoms, and \( N_a \) is the sum of their smallest adjacent bond angles (in degrees), calculate \( N_a / N_e \).
Correct answer · Option 3
\( 29.45 \)
Explanation
\( N_e = 2 + 3 + 4 + 5 + 6 = 20 \). Smallest adjacent bond angles: \( 180^\circ \), \( 120^\circ \), \( 109.5^\circ \), \( 90^\circ \), \( 90^\circ \). Sum \( N_a = 180 + 120 + 109.5 + 90 + 90 = 589.5^\circ \). Thus, \( N_a / N_e = 589.5 / 20 = 29.475 \approx 29.45 \).
