OnlineCBT
Physics · SYSTEMS OF PARTICLES AND ROTATIONAL MOTION
हिन्दीMatch List-I with List-II for bodies of mass \( M \) and radius \( R \) (or length \( L \)): List-I (Body and Axis) List-II (Moment of Inertia) A Circular disc about its diameter I \( \frac{1}{12} M L^2 \) B Thin rod of length \( L \) about perpendicular axis at mid-point II \( \frac{2}{5} M R^2 \) C Solid sphere about its diameter III \( \frac{1}{4} M R^2 \) D Solid cylinder about its longitudinal axis IV \( \frac{1}{2} M R^2 \) Choose the correct answer from the options given below:
Match List-I with List-II for bodies of mass \( M \) and radius \( R \) (or length \( L \)):
| List-I (Body and Axis) | List-II (Moment of Inertia) | ||
|---|---|---|---|
| A | Circular disc about its diameter | I | \( \frac{1}{12} M L^2 \) |
| B | Thin rod of length \( L \) about perpendicular axis at mid-point | II | \( \frac{2}{5} M R^2 \) |
| C | Solid sphere about its diameter | III | \( \frac{1}{4} M R^2 \) |
| D | Solid cylinder about its longitudinal axis | IV | \( \frac{1}{2} M R^2 \) |
Choose the correct answer from the options given below:
Correct answer · Option 4
A-(III), B-(I), C-(II), D-(IV)
Explanation
From Table 6.1: Disc about diameter = \( \frac{1}{4}MR^2 \); Rod about perpendicular mid-point = \( \frac{1}{12}ML^2 \); Solid sphere about diameter = \( \frac{2}{5}MR^2 \); Solid cylinder about axis = \( \frac{1}{2}MR^2 \).
