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Physics · LAWS OF MOTION
हिन्दीTwo masses \( m_1 = 3\text{ kg} \) and \( m_2 = 5\text{ kg} \) are suspended vertically from the ends of a light inextensible string passing over a smooth, mass-less pulley. If the system is released from rest, determine the tension \( T \) in the string and the acceleration \( a \) of the system. (Take \( g = 10\text{ m/s}^2 \))
Correct answer · Option 3
\( T = 37.5\text{ N} \) and \( a = 2.5\text{ m/s}^2 \)
Explanation
Acceleration \( a = \frac{m_2 - m_1}{m_1 + m_2} g = \frac{5 - 3}{8} \times 10 = 2.5\text{ m/s}^2 \). Tension \( T = \frac{2 m_1 m_2}{m_1 + m_2} g = \frac{2 \times 3 \times 5}{8} \times 10 = 37.5\text{ N} \).
