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Physics · PYQ NEET UG 2016(2)
हिन्दीA satellite of mass m is orbiting the earth (of radius R) at a height h from its surface. The total energy of the satellite in terms of \( g_0 \), the value of acceleration due to gravity at the earth's surface, is
Correct answer · Option 3
\( -\frac{mg_0R^2}{2(R+h)} \)
Explanation
Total energy of satellite \( E = -\frac{GMm}{2r} \). Substituting \( GM = g_0 R^2 \) and \( r = R+h \), we get \( E = -\frac{mg_0R^2}{2(R+h)} \).
